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If vec(a)= hat(i) - 2hat(j) + 5hat(k), v...

If `vec(a)= hat(i) - 2hat(j) + 5hat(k), vec(b)= 2hat(i) +hat(j)- 3hat(k)` then what is `(vec(a)- vec(b)).(3 vec(a) +vec(b))` equal to ?

A

106

B

`-106`

C

53

D

`-53`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \((\vec{a} - \vec{b}) \cdot (3\vec{a} + \vec{b})\) given the vectors: \[ \vec{a} = \hat{i} - 2\hat{j} + 5\hat{k} \] \[ \vec{b} = 2\hat{i} + \hat{j} - 3\hat{k} \] ### Step 1: Calculate \(\vec{a} - \vec{b}\) We start by subtracting vector \(\vec{b}\) from vector \(\vec{a}\): \[ \vec{a} - \vec{b} = (\hat{i} - 2\hat{j} + 5\hat{k}) - (2\hat{i} + \hat{j} - 3\hat{k}) \] Distributing the negative sign: \[ = \hat{i} - 2\hat{j} + 5\hat{k} - 2\hat{i} - \hat{j} + 3\hat{k} \] Now, combine the like terms: \[ = (\hat{i} - 2\hat{i}) + (-2\hat{j} - \hat{j}) + (5\hat{k} + 3\hat{k}) \] \[ = -\hat{i} - 3\hat{j} + 8\hat{k} \] ### Step 2: Calculate \(3\vec{a} + \vec{b}\) Next, we calculate \(3\vec{a} + \vec{b}\): \[ 3\vec{a} = 3(\hat{i} - 2\hat{j} + 5\hat{k}) = 3\hat{i} - 6\hat{j} + 15\hat{k} \] Now add \(\vec{b}\): \[ 3\vec{a} + \vec{b} = (3\hat{i} - 6\hat{j} + 15\hat{k}) + (2\hat{i} + \hat{j} - 3\hat{k}) \] Combining the like terms: \[ = (3\hat{i} + 2\hat{i}) + (-6\hat{j} + \hat{j}) + (15\hat{k} - 3\hat{k}) \] \[ = 5\hat{i} - 5\hat{j} + 12\hat{k} \] ### Step 3: Calculate the dot product \((\vec{a} - \vec{b}) \cdot (3\vec{a} + \vec{b})\) Now we need to find the dot product: \[ (\vec{a} - \vec{b}) \cdot (3\vec{a} + \vec{b}) = (-\hat{i} - 3\hat{j} + 8\hat{k}) \cdot (5\hat{i} - 5\hat{j} + 12\hat{k}) \] Calculating the dot product: \[ = (-1)(5) + (-3)(-5) + (8)(12) \] \[ = -5 + 15 + 96 \] \[ = 106 \] ### Final Answer Thus, the value of \((\vec{a} - \vec{b}) \cdot (3\vec{a} + \vec{b})\) is: \[ \boxed{106} \]
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  15. Let vec(a).vec(b) and vec(c ) be three mutually perpendicular vectors ...

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  17. A unit vector perpendicular to each of the vectors 2hat(i) - hat(j) + ...

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