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Consider the vectors a = i- 2j + k and b...

Consider the vectors `a = i- 2j + k and b= 4i- 4j + 7k`
What is the scalar projection of a on b?

A

1

B

`(19)/(9)`

C

`(17)/(9)`

D

`(23)/(9)`

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AI Generated Solution

The correct Answer is:
To find the scalar projection of vector **a** on vector **b**, we can use the formula: \[ \text{Scalar Projection of } \mathbf{a} \text{ on } \mathbf{b} = \frac{\mathbf{a} \cdot \mathbf{b}}{|\mathbf{b}|} \] Where: - \(\mathbf{a} \cdot \mathbf{b}\) is the dot product of vectors **a** and **b**. - \(|\mathbf{b}|\) is the magnitude (or length) of vector **b**. ### Step 1: Calculate the dot product \(\mathbf{a} \cdot \mathbf{b}\) Given: \[ \mathbf{a} = \mathbf{i} - 2\mathbf{j} + \mathbf{k} \] \[ \mathbf{b} = 4\mathbf{i} - 4\mathbf{j} + 7\mathbf{k} \] The dot product is calculated as follows: \[ \mathbf{a} \cdot \mathbf{b} = (1)(4) + (-2)(-4) + (1)(7) \] \[ = 4 + 8 + 7 \] \[ = 19 \] ### Step 2: Calculate the magnitude of vector **b** The magnitude of vector **b** is given by the formula: \[ |\mathbf{b}| = \sqrt{(4^2) + (-4^2) + (7^2)} \] \[ = \sqrt{16 + 16 + 49} \] \[ = \sqrt{81} \] \[ = 9 \] ### Step 3: Calculate the scalar projection Now we can substitute the values into the scalar projection formula: \[ \text{Scalar Projection of } \mathbf{a} \text{ on } \mathbf{b} = \frac{\mathbf{a} \cdot \mathbf{b}}{|\mathbf{b}|} = \frac{19}{9} \] ### Final Answer Thus, the scalar projection of vector **a** on vector **b** is: \[ \frac{19}{9} \] ---
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