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If the angle between the vectors hat(i)-...

If the angle between the vectors `hat(i)- m hat(j) and hat(j) + hat(k)` is `(pi)/(3)`, then what is the value of m?

A

0

B

2

C

`-2`

D

None of these

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The correct Answer is:
To solve the problem, we need to find the value of \( m \) given that the angle between the vectors \( \hat{i} - m \hat{j} \) and \( \hat{j} + \hat{k} \) is \( \frac{\pi}{3} \). ### Step-by-Step Solution: 1. **Identify the Vectors**: Let vector \( \mathbf{A} = \hat{i} - m \hat{j} \) and vector \( \mathbf{B} = \hat{j} + \hat{k} \). 2. **Use the Cosine Formula**: The cosine of the angle \( \theta \) between two vectors \( \mathbf{A} \) and \( \mathbf{B} \) is given by: \[ \cos \theta = \frac{\mathbf{A} \cdot \mathbf{B}}{|\mathbf{A}| |\mathbf{B}|} \] We know \( \theta = \frac{\pi}{3} \), so \( \cos \frac{\pi}{3} = \frac{1}{2} \). 3. **Calculate the Dot Product**: The dot product \( \mathbf{A} \cdot \mathbf{B} \) is calculated as follows: \[ \mathbf{A} \cdot \mathbf{B} = (\hat{i} - m \hat{j}) \cdot (\hat{j} + \hat{k}) = \hat{i} \cdot \hat{j} + \hat{i} \cdot \hat{k} - m \hat{j} \cdot \hat{j} - m \hat{j} \cdot \hat{k} \] Since \( \hat{i} \cdot \hat{j} = 0 \), \( \hat{i} \cdot \hat{k} = 0 \), \( \hat{j} \cdot \hat{j} = 1 \), and \( \hat{j} \cdot \hat{k} = 0 \), we have: \[ \mathbf{A} \cdot \mathbf{B} = 0 + 0 - m(1) - 0 = -m \] 4. **Calculate the Magnitudes**: The magnitude of \( \mathbf{A} \): \[ |\mathbf{A}| = \sqrt{1^2 + (-m)^2} = \sqrt{1 + m^2} \] The magnitude of \( \mathbf{B} \): \[ |\mathbf{B}| = \sqrt{0^2 + 1^2 + 1^2} = \sqrt{2} \] 5. **Set Up the Equation**: Substitute the values into the cosine formula: \[ \frac{1}{2} = \frac{-m}{\sqrt{1 + m^2} \cdot \sqrt{2}} \] Rearranging gives: \[ -m = \frac{1}{2} \cdot \sqrt{1 + m^2} \cdot \sqrt{2} \] Simplifying further: \[ -m = \frac{\sqrt{2}}{2} \sqrt{1 + m^2} \] 6. **Square Both Sides**: Squaring both sides to eliminate the square root: \[ m^2 = \left(\frac{\sqrt{2}}{2} \sqrt{1 + m^2}\right)^2 \] This expands to: \[ m^2 = \frac{2}{4}(1 + m^2) = \frac{1}{2}(1 + m^2) \] 7. **Rearranging the Equation**: Multiply both sides by 2 to eliminate the fraction: \[ 2m^2 = 1 + m^2 \] Rearranging gives: \[ 2m^2 - m^2 = 1 \implies m^2 = 1 \] 8. **Find the Values of \( m \)**: Taking the square root gives: \[ m = \pm 1 \] 9. **Check the Options**: The options provided are \( 0, 2, -2, \) and \( \text{none of these} \). Since \( m = 1 \) or \( m = -1 \) is not listed, the answer is \( \text{none of these} \). ### Final Answer: The value of \( m \) is \( \pm 1 \), and the answer is **none of these**.
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