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If |vec(a)|=10 |vec(b)|=2 and vec(a).vec...

If `|vec(a)|=10 |vec(b)|=2 and vec(a).vec(b)=12`, then what is the value of `|vec(a) xx vec(b)|` ?

A

12

B

16

C

20

D

24

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \(|\vec{a} \times \vec{b}|\), we can use the formula that relates the magnitudes of the vectors and their dot product: \[ |\vec{a} \times \vec{b}| = \sqrt{|\vec{a}|^2 |\vec{b}|^2 - (\vec{a} \cdot \vec{b})^2} \] ### Step-by-Step Solution: 1. **Identify the given values:** - \(|\vec{a}| = 10\) - \(|\vec{b}| = 2\) - \(\vec{a} \cdot \vec{b} = 12\) 2. **Substitute the values into the formula:** \[ |\vec{a} \times \vec{b}| = \sqrt{|\vec{a}|^2 |\vec{b}|^2 - (\vec{a} \cdot \vec{b})^2} \] becomes \[ |\vec{a} \times \vec{b}| = \sqrt{(10^2)(2^2) - (12)^2} \] 3. **Calculate \(|\vec{a}|^2\) and \(|\vec{b}|^2\):** - \(|\vec{a}|^2 = 10^2 = 100\) - \(|\vec{b}|^2 = 2^2 = 4\) 4. **Calculate \((\vec{a} \cdot \vec{b})^2\):** - \((\vec{a} \cdot \vec{b})^2 = 12^2 = 144\) 5. **Substitute these values back into the equation:** \[ |\vec{a} \times \vec{b}| = \sqrt{(100)(4) - 144} \] 6. **Calculate \(100 \times 4\):** - \(100 \times 4 = 400\) 7. **Now substitute back into the equation:** \[ |\vec{a} \times \vec{b}| = \sqrt{400 - 144} \] 8. **Calculate \(400 - 144\):** - \(400 - 144 = 256\) 9. **Finally, take the square root:** \[ |\vec{a} \times \vec{b}| = \sqrt{256} = 16 \] ### Final Answer: \[ |\vec{a} \times \vec{b}| = 16 \]
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