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Consider the plane passing through the p...

Consider the plane passing through the points `A(2,2,1),B(3,4,2) and C(7,0,6)`
What are the direction ratios of the normal to the plane

A

`lt1,0,0gt`

B

`lt0,1,0gt`

C

`lt1,0,-1gt`

D

None of these

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The correct Answer is:
To find the direction ratios of the normal to the plane passing through the points \( A(2,2,1) \), \( B(3,4,2) \), and \( C(7,0,6) \), we will follow these steps: ### Step 1: Find the vectors AB and AC First, we need to find the vectors \( \overrightarrow{AB} \) and \( \overrightarrow{AC} \). - The vector \( \overrightarrow{AB} = B - A = (3-2, 4-2, 2-1) = (1, 2, 1) \) - The vector \( \overrightarrow{AC} = C - A = (7-2, 0-2, 6-1) = (5, -2, 5) \) ### Step 2: Calculate the cross product of vectors AB and AC The direction ratios of the normal to the plane can be found by calculating the cross product of the vectors \( \overrightarrow{AB} \) and \( \overrightarrow{AC} \). Let: \[ \overrightarrow{AB} = (1, 2, 1) \] \[ \overrightarrow{AC} = (5, -2, 5) \] The cross product \( \overrightarrow{AB} \times \overrightarrow{AC} \) is given by the determinant: \[ \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ 1 & 2 & 1 \\ 5 & -2 & 5 \end{vmatrix} \] ### Step 3: Calculate the determinant Calculating the determinant, we have: \[ \hat{i} \begin{vmatrix} 2 & 1 \\ -2 & 5 \end{vmatrix} - \hat{j} \begin{vmatrix} 1 & 1 \\ 5 & 5 \end{vmatrix} + \hat{k} \begin{vmatrix} 1 & 2 \\ 5 & -2 \end{vmatrix} \] Calculating each of these 2x2 determinants: 1. \( \begin{vmatrix} 2 & 1 \\ -2 & 5 \end{vmatrix} = (2 \cdot 5) - (1 \cdot -2) = 10 + 2 = 12 \) 2. \( \begin{vmatrix} 1 & 1 \\ 5 & 5 \end{vmatrix} = (1 \cdot 5) - (1 \cdot 5) = 5 - 5 = 0 \) 3. \( \begin{vmatrix} 1 & 2 \\ 5 & -2 \end{vmatrix} = (1 \cdot -2) - (2 \cdot 5) = -2 - 10 = -12 \) Putting it all together, we get: \[ \overrightarrow{AB} \times \overrightarrow{AC} = 12\hat{i} - 0\hat{j} - 12\hat{k} = (12, 0, -12) \] ### Step 4: Direction Ratios The direction ratios of the normal to the plane are \( (12, 0, -12) \). ### Final Answer The direction ratios of the normal to the plane are \( (12, 0, -12) \). ---
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