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Consider a sphere passing through the or...

Consider a sphere passing through the origin and the points `(2,1,-1),(1,5,-4),(-2,4,-6)`
Consider the folllowing statements
I. The sphere pases through the point `(0,4,0)`
II. The point `(1,1,1)` is at a distance of 5 unit from the center of the sphere
Which of the above statement(s) is/are correct?

A

A. Only I

B

B. Only II

C

C. Both I and II

D

D. Neither I nor II

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the equation of the sphere that passes through the origin and the points (2, 1, -1), (1, 5, -4), and (-2, 4, -6). We can then verify the two statements provided. ### Step 1: Write the equation of the sphere The general equation of a sphere that passes through the origin is given by: \[ x^2 + y^2 + z^2 + 2ux + 2vy + 2wz = 0 \] where \( (u, v, w) \) are the coordinates of the center of the sphere. ### Step 2: Substitute the points into the sphere's equation We will substitute each of the three points into the equation to form a system of equations. **For the point (2, 1, -1):** \[ 2^2 + 1^2 + (-1)^2 + 2u(2) + 2v(1) + 2w(-1) = 0 \] \[ 4 + 1 + 1 + 4u + 2v - 2w = 0 \] \[ 6 + 4u + 2v - 2w = 0 \quad \text{(Equation 1)} \] **For the point (1, 5, -4):** \[ 1^2 + 5^2 + (-4)^2 + 2u(1) + 2v(5) + 2w(-4) = 0 \] \[ 1 + 25 + 16 + 2u + 10v - 8w = 0 \] \[ 42 + 2u + 10v - 8w = 0 \quad \text{(Equation 2)} \] **For the point (-2, 4, -6):** \[ (-2)^2 + 4^2 + (-6)^2 + 2u(-2) + 2v(4) + 2w(-6) = 0 \] \[ 4 + 16 + 36 - 4u + 8v - 12w = 0 \] \[ 56 - 4u + 8v - 12w = 0 \quad \text{(Equation 3)} \] ### Step 3: Solve the system of equations We now have three equations: 1. \( 4u + 2v - 2w = -6 \) 2. \( 2u + 10v - 8w = -42 \) 3. \( -4u + 8v - 12w = -56 \) We can solve these equations simultaneously to find the values of \( u, v, \) and \( w \). From Equation 1: \[ 4u + 2v - 2w = -6 \quad \text{(1)} \] From Equation 2: \[ 2u + 10v - 8w = -42 \quad \text{(2)} \] From Equation 3: \[ -4u + 8v - 12w = -56 \quad \text{(3)} \] We can express \( w \) in terms of \( u \) and \( v \) from Equation (1): \[ 2w = 4u + 2v + 6 \implies w = 2u + v + 3 \] Substituting \( w \) into Equations (2) and (3) will allow us to solve for \( u \) and \( v \). ### Step 4: Substitute \( w \) into the equations Substituting \( w \) into Equation (2): \[ 2u + 10v - 8(2u + v + 3) = -42 \] \[ 2u + 10v - 16u - 8v - 24 = -42 \] \[ -14u + 2v + 24 = -42 \] \[ -14u + 2v = -66 \implies 7u - v = 33 \quad \text{(4)} \] Substituting \( w \) into Equation (3): \[ -4u + 8v - 12(2u + v + 3) = -56 \] \[ -4u + 8v - 24u - 12v - 36 = -56 \] \[ -28u - 4v - 36 = -56 \] \[ -28u - 4v = -20 \implies 7u + v = 5 \quad \text{(5)} \] ### Step 5: Solve Equations (4) and (5) Now we have: 1. \( 7u - v = 33 \) 2. \( 7u + v = 5 \) Adding these two equations: \[ (7u - v) + (7u + v) = 33 + 5 \] \[ 14u = 38 \implies u = \frac{19}{7} \] Substituting \( u \) back into Equation (4): \[ 7 \left( \frac{19}{7} \right) - v = 33 \implies 19 - v = 33 \implies v = -14 \] Substituting \( u \) and \( v \) back into the expression for \( w \): \[ w = 2 \left( \frac{19}{7} \right) + (-14) + 3 = \frac{38}{7} - 14 + 3 = \frac{38}{7} - \frac{98}{7} + \frac{21}{7} = \frac{-39}{7} \] ### Step 6: Write the equation of the sphere Now we have \( u = \frac{19}{7}, v = -14, w = \frac{-39}{7} \). The equation of the sphere becomes: \[ x^2 + y^2 + z^2 + 2 \left( \frac{19}{7} \right)x - 28y - \frac{78}{7}z = 0 \] ### Step 7: Verify the statements **Statement I: The sphere passes through the point (0, 4, 0)** Substituting \( (0, 4, 0) \) into the sphere's equation: \[ 0 + 16 + 0 + 0 - 28(4) + 0 = 0 \] \[ 16 - 112 = -96 \neq 0 \quad \text{(False)} \] **Statement II: The point (1, 1, 1) is at a distance of 5 units from the center of the sphere** The center of the sphere is \( (-u, -v, -w) = \left(-\frac{19}{7}, 14, \frac{39}{7}\right) \). Calculating the distance from \( (1, 1, 1) \): \[ d = \sqrt{\left(1 + \frac{19}{7}\right)^2 + \left(1 - 14\right)^2 + \left(1 - \frac{39}{7}\right)^2} \] Calculating each term: 1. \( 1 + \frac{19}{7} = \frac{26}{7} \) 2. \( 1 - 14 = -13 \) 3. \( 1 - \frac{39}{7} = \frac{-32}{7} \) Now calculating the distance: \[ d = \sqrt{\left(\frac{26}{7}\right)^2 + (-13)^2 + \left(\frac{-32}{7}\right)^2} \] \[ = \sqrt{\frac{676}{49} + 169 + \frac{1024}{49}} = \sqrt{\frac{676 + 169 \cdot 49 + 1024}{49}} = \sqrt{\frac{676 + 8281 + 1024}{49}} = \sqrt{\frac{9981}{49}} = \frac{\sqrt{9981}}{7} \] Calculating \( \sqrt{9981} \) gives approximately \( 99.905 \), thus: \[ d \approx \frac{99.905}{7} \approx 14.27 \quad \text{(False)} \] ### Conclusion Both statements are incorrect. **Final Answer:** Neither statement I nor II is correct.
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