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Consider the spheres x^2+y^2+z^2-4y+3=0 ...

Consider the spheres `x^2+y^2+z^2-4y+3=0 and x^2+y^2+z^2+2x+4z-4=0`
What is the distance between the centres of the two spheres ?

A

5 unit

B

4 unit

C

3 unit

D

2 unit

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The correct Answer is:
To find the distance between the centers of the two spheres given by the equations \(x^2 + y^2 + z^2 - 4y + 3 = 0\) and \(x^2 + y^2 + z^2 + 2x + 4z - 4 = 0\), we will follow these steps: ### Step 1: Rewrite the first sphere's equation The first sphere's equation is: \[ x^2 + y^2 + z^2 - 4y + 3 = 0 \] We can rearrange this equation: \[ x^2 + (y^2 - 4y) + z^2 + 3 = 0 \] Next, we complete the square for the \(y\) term: \[ y^2 - 4y = (y - 2)^2 - 4 \] Substituting this back into the equation gives: \[ x^2 + (y - 2)^2 - 4 + z^2 + 3 = 0 \] This simplifies to: \[ x^2 + (y - 2)^2 + z^2 - 1 = 0 \] Thus, we have: \[ x^2 + (y - 2)^2 + z^2 = 1 \] From this, we can identify the center of the first sphere as: \[ C_1(0, 2, 0) \] and the radius \(r_1 = 1\). ### Step 2: Rewrite the second sphere's equation The second sphere's equation is: \[ x^2 + y^2 + z^2 + 2x + 4z - 4 = 0 \] We rearrange this equation: \[ (x^2 + 2x) + y^2 + (z^2 + 4z) - 4 = 0 \] Next, we complete the square for the \(x\) and \(z\) terms: \[ x^2 + 2x = (x + 1)^2 - 1 \] \[ z^2 + 4z = (z + 2)^2 - 4 \] Substituting these back into the equation gives: \[ ((x + 1)^2 - 1) + y^2 + ((z + 2)^2 - 4) - 4 = 0 \] This simplifies to: \[ (x + 1)^2 + y^2 + (z + 2)^2 - 9 = 0 \] Thus, we have: \[ (x + 1)^2 + y^2 + (z + 2)^2 = 9 \] From this, we can identify the center of the second sphere as: \[ C_2(-1, 0, -2) \] and the radius \(r_2 = 3\). ### Step 3: Calculate the distance between the centers Now, we can calculate the distance \(d\) between the centers \(C_1(0, 2, 0)\) and \(C_2(-1, 0, -2)\) using the distance formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2} \] Substituting the coordinates: \[ d = \sqrt{((-1) - 0)^2 + (0 - 2)^2 + ((-2) - 0)^2} \] This simplifies to: \[ d = \sqrt{(-1)^2 + (-2)^2 + (-2)^2} \] Calculating each term: \[ d = \sqrt{1 + 4 + 4} = \sqrt{9} = 3 \] ### Final Answer The distance between the centers of the two spheres is \(3\) units. ---
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