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Consider the following relations among a...

Consider the following relations among angles `alpha,beta and gamma` made by a vector with the coordinate axes.
I. `cos2alpha+cos2beta+cos2gamma=-1`
II. `sin^2alpha+sin^2beta+sin^2gamma=1`
Which of the above statement is/are correct

A

Only I

B

Only II

C

Both I and II

D

Niether I nor II

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correctness of the given statements regarding the angles \( \alpha, \beta, \) and \( \gamma \) made by a vector with the coordinate axes, we will analyze each statement step by step. ### Step 1: Understanding the Direction Cosines The direction cosines of a vector with respect to the coordinate axes are defined as: - \( l = \cos \alpha \) (angle with x-axis) - \( m = \cos \beta \) (angle with y-axis) - \( n = \cos \gamma \) (angle with z-axis) From the properties of direction cosines, we know that: \[ l^2 + m^2 + n^2 = 1 \] This can be rewritten as: \[ \cos^2 \alpha + \cos^2 \beta + \cos^2 \gamma = 1 \tag{1} \] ### Step 2: Analyzing Statement I The first statement is: \[ \cos 2\alpha + \cos 2\beta + \cos 2\gamma = -1 \] Using the double angle formula for cosine: \[ \cos 2\theta = 2\cos^2 \theta - 1 \] we can express \( \cos 2\alpha, \cos 2\beta, \) and \( \cos 2\gamma \) in terms of \( \cos^2 \alpha, \cos^2 \beta, \) and \( \cos^2 \gamma \): \[ \cos 2\alpha = 2\cos^2 \alpha - 1 \] \[ \cos 2\beta = 2\cos^2 \beta - 1 \] \[ \cos 2\gamma = 2\cos^2 \gamma - 1 \] Substituting these into the first statement gives: \[ (2\cos^2 \alpha - 1) + (2\cos^2 \beta - 1) + (2\cos^2 \gamma - 1) = -1 \] Simplifying this: \[ 2(\cos^2 \alpha + \cos^2 \beta + \cos^2 \gamma) - 3 = -1 \] Using equation (1): \[ 2(1) - 3 = -1 \] Thus, the first statement is **true**. ### Step 3: Analyzing Statement II The second statement is: \[ \sin^2 \alpha + \sin^2 \beta + \sin^2 \gamma = 1 \] Using the identity \( \sin^2 \theta + \cos^2 \theta = 1 \), we can express \( \sin^2 \alpha, \sin^2 \beta, \) and \( \sin^2 \gamma \) as: \[ \sin^2 \alpha = 1 - \cos^2 \alpha \] \[ \sin^2 \beta = 1 - \cos^2 \beta \] \[ \sin^2 \gamma = 1 - \cos^2 \gamma \] Substituting these into the second statement gives: \[ (1 - \cos^2 \alpha) + (1 - \cos^2 \beta) + (1 - \cos^2 \gamma) = 1 \] This simplifies to: \[ 3 - (\cos^2 \alpha + \cos^2 \beta + \cos^2 \gamma) = 1 \] Using equation (1): \[ 3 - 1 = 1 \] Thus, we have: \[ 2 = 1 \] This is **false**. ### Conclusion Based on the analysis: - Statement I is **true**. - Statement II is **false**. Thus, the correct answer is that **only Statement I is correct**.
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