Home
Class 14
MATHS
Consider the equation x+|y|=2y Which o...

Consider the equation `x+|y|=2y`
Which of the following statements are not correct ?
1. y as a function of x is not defined for all real x.
2. y as a function of x is not continuous at `x=0`
3. y as a function of x is differentiable for all x.
Select the correct answer using the code given below :

A

A) 1 and 2

B

B) 2 and 3

C

C) 1 and 3

D

D) 1, 2 and 3

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the equation \( x + |y| = 2y \) and evaluate the three statements given. ### Step 1: Analyze the equation The equation can be split into two cases based on the value of \( y \): 1. **Case 1**: \( y \geq 0 \) (where \( |y| = y \)) \[ x + y = 2y \] Rearranging gives: \[ x = 2y - y \implies x = y \] Therefore, when \( y \geq 0 \), we have \( y = x \). 2. **Case 2**: \( y < 0 \) (where \( |y| = -y \)) \[ x - y = 2y \] Rearranging gives: \[ x = 2y + y \implies x = 3y \implies y = \frac{x}{3} \] Therefore, when \( y < 0 \), we have \( y = \frac{x}{3} \). ### Step 2: Determine the values of \( y \) based on \( x \) From the analysis: - For \( x \geq 0 \), \( y = x \). - For \( x < 0 \), \( y = \frac{x}{3} \). ### Step 3: Evaluate the statements 1. **Statement 1**: "y as a function of x is not defined for all real x." - **Analysis**: The function is defined for all real \( x \) since we have explicit equations for both cases. Thus, this statement is **not correct**. 2. **Statement 2**: "y as a function of x is not continuous at \( x = 0 \)." - **Analysis**: At \( x = 0 \), both cases yield \( y = 0 \). Therefore, the function is continuous at \( x = 0 \). This statement is also **not correct**. 3. **Statement 3**: "y as a function of x is differentiable for all x." - **Analysis**: To check differentiability, we need to find the derivatives: - For \( x > 0 \), \( y = x \) gives \( \frac{dy}{dx} = 1 \). - For \( x < 0 \), \( y = \frac{x}{3} \) gives \( \frac{dy}{dx} = \frac{1}{3} \). - At \( x = 0 \), the left-hand derivative is \( \frac{1}{3} \) and the right-hand derivative is \( 1 \). Since these two derivatives are not equal, \( y \) is not differentiable at \( x = 0 \). Thus, this statement is **not correct**. ### Conclusion All three statements are not correct. Therefore, the correct answer is that statements 1, 2, and 3 are all incorrect.
Promotional Banner

Similar Questions

Explore conceptually related problems

Consider the equation x + |y| = 2y. Which of the following statements are not correct?I. y as a function of x is not defined for all real x.II. y as a function of x is not continuous at x=0.III. y as a function of x is differentiable for all x.Select the correct answer using the codes given below.

Consider the equation x+|y|=2y . Which of the following statements are not correct? yas a function of x is not defined for all real x. yas a function of x is not continuous at x=0. yas a function of x is differentiable for all x. Select the correct answer using the code given below.

If x+|y|=2y, then y as a function of x is

Consider the equation x+|y|=2y . What is the derivative of y as a function of x with respect to x for xlt0 ?

Let f(x+y) = f(x) + f(y) for all x and y. If the function f (x) is continuous at x = 0 , then show that f (x) is continuous at all x.

Let f(x+y)=f(x)+f(y) for all x and y If the function f(x) is continuous at x=0 show that f(x) is continuous for all x

Consider the following statements : 1. The function f(x)=3sqrtx is continuous at all x except at x=0. 2. The function f(x)=[x] is continuous at x=2.99 where [.] is the bracket function. Which of the above statements is/are correct ?