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Consider the equation x+|y|=2y What i...

Consider the equation `x+|y|=2y`
What is the derivative of y as a function of x with respect x for `xlt0` ?

A

2

B

1

C

`1/2`

D

`1/3`

Text Solution

AI Generated Solution

The correct Answer is:
To find the derivative of \( y \) as a function of \( x \) with respect to \( x \) for \( x < 0 \) given the equation \( x + |y| = 2y \), we can follow these steps: ### Step 1: Analyze the equation The equation given is: \[ x + |y| = 2y \] For \( x < 0 \), we need to consider the cases for \( |y| \). The absolute value function \( |y| \) can be expressed as: - \( |y| = y \) if \( y \geq 0 \) - \( |y| = -y \) if \( y < 0 \) ### Step 2: Solve for \( y \) when \( y < 0 \) Since we are interested in the case where \( x < 0 \), we will assume \( y < 0 \). Thus, we replace \( |y| \) with \( -y \): \[ x - y = 2y \] Rearranging this gives: \[ x = 2y + y \] \[ x = 3y \] Now, solving for \( y \): \[ y = \frac{x}{3} \] ### Step 3: Differentiate \( y \) with respect to \( x \) Now that we have \( y \) as a function of \( x \): \[ y = \frac{x}{3} \] We can differentiate \( y \) with respect to \( x \): \[ \frac{dy}{dx} = \frac{1}{3} \] ### Conclusion Thus, the derivative of \( y \) with respect to \( x \) for \( x < 0 \) is: \[ \frac{dy}{dx} = \frac{1}{3} \]
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