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A man was 32 years of age when he had hi...

A man was 32 years of age when he had his first son. His wise was 35 years of age when his son attained the age of 7 years. The difference in age between the man and his wife is

A

7 years

B

3 years

C

5 years

D

4 years

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The correct Answer is:
To find the age difference between the man and his wife, we can follow these steps: ### Step 1: Determine the man's age when his son was born. The man was 32 years old when he had his first son. ### Step 2: Determine the wife's age when the son was 7 years old. We know that when the son was 7 years old, the wife was 35 years old. ### Step 3: Calculate the man's age when the son was 7 years old. Since the son was 7 years old, we need to add 7 years to the man's age when the son was born (32 years). - Man's age when son was 7 = 32 years + 7 years = 39 years. ### Step 4: Calculate the age difference between the man and his wife. Now we have the man's age (39 years) and the wife's age (35 years). To find the age difference, we subtract the wife's age from the man's age. - Age difference = Man's age - Wife's age = 39 years - 35 years = 4 years. ### Conclusion: The difference in age between the man and his wife is 4 years. ---

To find the age difference between the man and his wife, we can follow these steps: ### Step 1: Determine the man's age when his son was born. The man was 32 years old when he had his first son. ### Step 2: Determine the wife's age when the son was 7 years old. We know that when the son was 7 years old, the wife was 35 years old. ...
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