Neela is now three times as old as her daughter Leela. Ten years back, Neela was five times as old as Leela. The age of Leela is

Options

A. 15 A.
B. 25 B.
C. 30 C.
D. 20 D.

Explanation

To solve the problem step by step, we will define the ages of Neela and Leela using algebra.

### Step 1: Define Variables
Let Leela's current age be \( L \) years. Since Neela is three times as old as Leela, we can express Neela's current age as:
\[ N = 3L \]
where \( N \) is Neela's age.

**Hint:** Define variables for the ages based on the relationships given in the problem.

### Step 2: Set Up the Equation for the Past
According to the problem, ten years ago, Neela was five times as old as Leela. Therefore, we can express their ages ten years ago as:
- Leela's age ten years ago: \( L - 10 \)
- Neela's age ten years ago: \( N - 10 = 3L - 10 \)

From the information given, we can set up the equation:
\[ N - 10 = 5(L - 10) \]

**Hint:** Write the ages in terms of the defined variables and set up an equation based on the past relationship.

### Step 3: Substitute and Simplify
Now, substitute \( N = 3L \) into the equation:
\[ 3L - 10 = 5(L - 10) \]

Expanding the right side:
\[ 3L - 10 = 5L - 50 \]

**Hint:** Substitute the expression for Neela's age into the equation and simplify both sides.

### Step 4: Rearrange the Equation
Now, rearranging the equation gives:
\[ 3L - 10 + 50 = 5L \]
\[ 3L + 40 = 5L \]

Subtract \( 3L \) from both sides:
\[ 40 = 5L - 3L \]
\[ 40 = 2L \]

**Hint:** Move all terms involving \( L \) to one side to isolate \( L \).

### Step 5: Solve for Leela's Age
Now, divide both sides by 2 to find \( L \):
\[ L = \frac{40}{2} = 20 \]

So, Leela's current age is:
\[ L = 20 \text{ years} \]

**Hint:** Perform the final calculation to find the value of \( L \).

### Conclusion
Leela is currently 20 years old.