What is the sum of the squares of the digits 1 to 9 ?

Options

A. 105
B. 385
C. 260
D. 285

Explanation

To find the sum of the squares of the digits from 1 to 9, we can follow these steps:

### Step 1: Identify the digits
The digits we need to consider are 1, 2, 3, 4, 5, 6, 7, 8, and 9.

### Step 2: Write down the squares of each digit
We will calculate the square of each digit:
- \(1^2 = 1\)
- \(2^2 = 4\)
- \(3^2 = 9\)
- \(4^2 = 16\)
- \(5^2 = 25\)
- \(6^2 = 36\)
- \(7^2 = 49\)
- \(8^2 = 64\)
- \(9^2 = 81\)

### Step 3: Sum the squares
Now, we will add all these squares together:
\[ 1 + 4 + 9 + 16 + 25 + 36 + 49 + 64 + 81 \]

### Step 4: Perform the addition
Let's add them step by step:
1. \(1 + 4 = 5\)
2. \(5 + 9 = 14\)
3. \(14 + 16 = 30\)
4. \(30 + 25 = 55\)
5. \(55 + 36 = 91\)
6. \(91 + 49 = 140\)
7. \(140 + 64 = 204\)
8. \(204 + 81 = 285\)

### Final Result
The sum of the squares of the digits from 1 to 9 is \(285\).