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Some equations are solved on the basis o...

Some equations are solved on the basis of a certain system. On the same basis find out the correct answer for the unsolved equation.
4-5-1 = 514, 3-5-6 = 563. 0-6-8 = ?

A

A) 680

B

B) 860

C

C) 068

D

D) 806

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to identify the pattern used in the given equations and apply it to the unsolved equation. ### Given Equations: 1. \( 4 - 5 - 1 = 514 \) 2. \( 3 - 5 - 6 = 563 \) ### Analyzing the Pattern: - In the first equation, the output \( 514 \) can be derived from the input numbers \( 4, 5, 1 \) by rearranging them. - The second number \( 5 \) is placed first, followed by the third number \( 1 \), and finally the first number \( 4 \). - So, \( 5 \) (second number), \( 1 \) (third number), \( 4 \) (first number) gives us \( 514 \). - In the second equation, the output \( 563 \) is derived similarly: - The second number \( 5 \) is placed first, followed by the third number \( 6 \), and then the first number \( 3 \). - Thus, \( 5 \) (second number), \( 6 \) (third number), \( 3 \) (first number) gives us \( 563 \). ### Applying the Same Logic: Now, we need to apply the same pattern to the unsolved equation \( 0 - 6 - 8 \). 1. Identify the numbers: - First number: \( 0 \) - Second number: \( 6 \) - Third number: \( 8 \) 2. Rearranging based on the observed pattern: - The second number \( 6 \) comes first. - The third number \( 8 \) comes second. - The first number \( 0 \) comes last. So, the output will be \( 6 \) (second number), \( 8 \) (third number), \( 0 \) (first number), which gives us \( 680 \). ### Final Answer: Thus, the answer to the equation \( 0 - 6 - 8 \) is \( 680 \). ---

To solve the problem, we need to identify the pattern used in the given equations and apply it to the unsolved equation. ### Given Equations: 1. \( 4 - 5 - 1 = 514 \) 2. \( 3 - 5 - 6 = 563 \) ### Analyzing the Pattern: - In the first equation, the output \( 514 \) can be derived from the input numbers \( 4, 5, 1 \) by rearranging them. ...
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