Town A and Town B were 600 km apart. Joshua left town A for town B and travelled at an average speed of 65 km/h. At the same time, Menon left town B for town A. The two of them met 5 hours later. Find Menon's average speed.

Options

A. 55 km/h
B. 60 km/h
C. 65 km/h
D. 120 km/h

Explanation

To solve the problem step by step, we will follow these instructions:

### Step 1: Understand the problem
We know that Town A and Town B are 600 km apart. Joshua travels from Town A to Town B at a speed of 65 km/h, and Menon travels from Town B to Town A. They meet after 5 hours.

**Hint:** Identify the key information: distances, speeds, and time.

### Step 2: Define the variables
Let Menon's speed be \( A \) km/h.

**Hint:** Assign a variable to the unknown speed to simplify calculations.

### Step 3: Calculate the distance covered by Joshua
In 5 hours, Joshua travels:
\[ \text{Distance} = \text{Speed} \times \text{Time} = 65 \text{ km/h} \times 5 \text{ h} = 325 \text{ km} \]

**Hint:** Use the formula for distance (Distance = Speed × Time) to find how far Joshua travels.

### Step 4: Calculate the distance covered by Menon
Since the total distance between Town A and Town B is 600 km, the distance covered by Menon when they meet is:
\[ \text{Distance covered by Menon} = 600 \text{ km} - 325 \text{ km} = 275 \text{ km} \]

**Hint:** Subtract the distance Joshua traveled from the total distance to find how far Menon traveled.

### Step 5: Calculate Menon's speed
Menon also traveled for 5 hours. Therefore, his speed can be calculated as:
\[ A = \frac{\text{Distance}}{\text{Time}} = \frac{275 \text{ km}}{5 \text{ h}} = 55 \text{ km/h} \]

**Hint:** Use the same distance formula to find Menon's speed.

### Final Answer
Menon's average speed is \( 55 \) km/h.

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