Home
Class 14
MATHS
Of four numbers whose average is 60, the...

Of four numbers whose average is 60, the first is `(1)/(4)` th of the sum of last three. The first number is

A

15

B

45

C

42

D

48

Text Solution

Verified by Experts

The correct Answer is:
D
Suppose the four numbers are respectively a, b, c and d.
`a+b+c+d=4xx60=240`
`a=(1)/(4)(b+c+d)`
Suppose, b+c+d=y
Now,
`(1)/(4)y+y=240`
`=y+4y=240xx4`
`:.y=(960)/(5)=192`
`:.a=240-192=48`
Promotional Banner

Topper's Solved these Questions

  • ARITHMETICAL PROBLEMS

    KIRAN PUBLICATION|Exercise TYPE-VI|16 Videos

  • ARITHMETICAL PROBLEMS

    KIRAN PUBLICATION|Exercise TYPE-VII|6 Videos

  • ARITHMETICAL PROBLEMS

    KIRAN PUBLICATION|Exercise TYPE-IV|23 Videos

  • ALLIGATION OR MIXTURES

    KIRAN PUBLICATION|Exercise TEST YOURSELF|27 Videos

  • AVERAGE

    KIRAN PUBLICATION|Exercise TYPE-X|48 Videos

Similar Questions

Explore conceptually related problems

Of four numbers whose average is 60, the first is one-fourth of the sum of the last three.The first number is (a) 15 (b) 42 (c) 45 (d) 48

Of the three numbers whose average is 40, the first is 1/3rd of the sum of other two. What is the first number?

Out of four numbers, the average of the first three is 15 and that of the last three is 16. If the last number is 19, the first is