A father increases pocket money of his son by 20%. If son gets 300 after increase, find his pocket money before increase.

Options

A. Rs 250
B. Rs 240
C. Rs 200
D. Rs 230

Explanation

To solve the problem step by step, we will find the son's pocket money before the increase.

### Step-by-Step Solution:

1. **Understand the Problem**:
The father increases the son's pocket money by 20%. After the increase, the son receives 300. We need to find out how much he was receiving before the increase.

2. **Define the Original Pocket Money**:
Let the original pocket money (before the increase) be represented as \( x \).

3. **Calculate the Increased Amount**:
Since the pocket money is increased by 20%, the new amount can be expressed as:
\[ \text{New Pocket Money} = x + 0.2x = 1.2x \]

4. **Set Up the Equation**:
According to the problem, after the increase, the son receives 300. Therefore, we can set up the equation:
\[ 1.2x = 300 \]

5. **Solve for \( x \)**:
To find \( x \), divide both sides of the equation by 1.2:
\[ x = \frac{300}{1.2} \]

6. **Calculate \( x \)**:
Performing the division:
\[ x = 250 \]

7. **Conclusion**:
The pocket money before the increase was \( 250 \).

### Final Answer:
The son's pocket money before the increase was **250**.