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The present ages of three friends are in...

The present ages of three friends are in the proportions 6:7: 8. Five years ago, the sum of their ages was 48 years. Find out their present ages in years.

A

24, 28, 32

B

18, 21, 24

C

30, 35, 40

D

12, 14, 16

Text Solution

Verified by Experts

The correct Answer is:
B

Suppose the present ages of three friends are respectively 6x years, 7x years and 8x years.
Five years ago their ages were : 6x-5 years, 7x-5 years 8x-5 years
According to question,
`(6x-5)+(7x-5)+(8x-5)=48`
`implies21x-15=48`
`implies21x=48+15`
`:.x=(63)/(21)=3`
Now, the present ages of the three friends
`6x=6xx3=18` years
`7x=7xx3=21` years
`8x=8xx3=24` years
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