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An alternating voltage E=200sqrt(2)sin(1...

An alternating voltage `E=200sqrt(2)sin(100t)` is connected to a `1` microfarad capacitor through an AC ammeter. The reading of the ammeter shall be

A

10 mA

B

50mA

C

20mA

D

40 mA

Text Solution

Verified by Experts

The correct Answer is:
C
`E_0 = 200 sqrt(2) V and omega= 100 rad .//s`
So ` X_c = (1)/( omegac) = (1)/(100 xx 10^(-6)) =10^(4) Omega`
As ammeter reads rms value of current
` therefore I_(rms) = (E_(rms))/(Z ) = (E_0)/((sqrt(2))X_c)`
`=(200 sqrt(2))/(sqrt(2)xx 10^4)`
` = 20 mA`
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