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The equation of tangent of y^(2) = 12 x...

The equation of tangent of ` y^(2) = 12 x` and making an angle `(pi)/(3)` with X - axis is . . . .

A

`pm y - sqrt(3) x + sqrt(3) = 0 `

B

` pm y + sqrt(3) x + 3 = 0 `

C

` pm y - sqrt(3) x - sqrt(3) = 0 `

D

` pm y + sqrt(3) x - 3 = 0 `

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