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int(0)^(pi//2) (x-[sin x]) dx= (where [...

`int_(0)^(pi//2) (x-[sin x]) dx`= ___ (where [x] = greatest integer not greater than x)

A

`(pi^(2))/(8)-2`

B

`(pi^(2))/(4)-1`

C

`(pi^(2))/(8)-1`

D

`(pi^(2))/(8)`

Text Solution

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The correct Answer is:
D
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