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A proton is moving perpendicular to a un...

A proton is moving perpendicular to a uniform magnetic field of 2.5 tesla with 2MeV kinetic energy. The force on the proton is ______ .

A

`8xx10^(-12)`

B

`8xx10^(-11)`

C

`3xx10^(-11)`

D

`3xx10^(-10)`

Text Solution

Verified by Experts

The correct Answer is:
A
Force on moving charge in magnetic field
`F=qvNsintheta`
but `theta=90`
F = qvB
Hence velocity `v=sqrt((2E)/m)` { E is kinetic energy of proton}
putting the values we get
`F=5.6xx10^(-12)N`
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