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In davision -Germer experiment electron ...

In davision -Germer experiment electron emitted from filament is accelerated by V volt.Its de-Broglie wavelength will be……..

A

`(2Vem)/(sqrth)`

B

`(sqrth)/(2Vem)`

C

`(sqrt(2Vem))/(h)`

D

`(h)/(sqrt(2Vem))`

Text Solution

Verified by Experts

The correct Answer is:
D
Kinetic energy `1/2mv^2=eV`
`v=sqrt((2eV)/m)`
Wavelength `lamda=h/(mv)`
`lamda=h/(msqrt((2eV)/m))=h/(sqrt(2eVm))`
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