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Photons of energy 1 eV and 2.5 eV sucess...

Photons of energy 1 eV and 2.5 eV sucesseively illuminate a metal,whose work function is 0.5 eV,the ratio of maximum speed of emitted electron is…..

A

`1:3`

B

`1:2`

C

`3:1`

D

`2:1`

Text Solution

Verified by Experts

The correct Answer is:
B
Energy of photon `E=phi+1/2mv^2`
`V_("max")=sqrt((2(E-phi))/m)`
So putting values
`(v_("max1"))/(v_("max2"))=sqrt((1-0.5)/(2.5-0.5))`
`(v_("max1"))/(v_("max2"))=1/2`
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