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A lamp consumes only 50% of maximum powe...

A lamp consumes only 50% of maximum power in an A.C. circuit. What is the phase difference between the applied voltage and the circuit current ?

A

`(pi)/(4)`

B

`(pi)/(3)`

C

`(pi)/(6)`

D

`(pi)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`P_("avg")= V_("rms")I_("rms")cosphi`
`P_("max")= V_("rms")I_("rms")`
`implies (V_("rms")I_("rms"))/(2)= V_("rms")I_("rms")cosphi`
`implies cosphi= (1)/(2)`
`phi= (pi)/(3)`
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