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The wavelength of photon having energy o...

The wavelength of photon having energy of 35 keV is ……..
`(h=6.625xx10^(-34)J-s, c=3xx10^(8)ms^(-1), 1eV=1.6xx10^(-19)J)`.

A

`3.5 xx 10^(-12) m`

B

`35Å`

C

3.5 nm

D

`3.5Å`

Text Solution

Verified by Experts

The correct Answer is:
A
`lambda= (hc)/(E_(lambda))= (6.625 xx 10^(-34) xx 3 xx 10^(8))/(35 xx 10^(3) xx 1.6 xx 10^(-19))m= 0.35 xx 10^(-10)m= 35 xx 10^(-12) m`
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