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In X-ray tube the potential difference b...

In X-ray tube the potential difference between the anode and the cathode is 20 kV and the current flowing is 1.6 mA. The number of electrons striking the anode in 1s is ..... (Take `e=1.6xx10^(-19)C)`

A

`10^(14)`

B

`1.25xx10^(16)`

C

`10^(16)`

D

`6.25 xx10^(10)`

Text Solution

Verified by Experts

The correct Answer is:
C
`1.6xx 10^(-3) = q/t`
`implies q= 16 xx 10^(-3) C`
ne `=1.6xx10^(-3)`
`n xx 1.6xx10^(-19)`
`= 1.6xx10^(-3)`
`n= 10^(16)`
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