Home
Class 12
PHYSICS
A sine voltage having maximum value of 2...

A sine voltage having maximum value of 283 V & frequency of 50 Hz is applied to LCR series connection where R=3 `Omega`, L = 25.48 mH & C=796 `mu`F. Then impedence is ________ at resonance condition.

A

3 `Omega`

B

5 `Omega`

C

15 `Omega`

D

4 `Omega`

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

A sinusoidal voltage of peak value of 283 V and frequency 50 Hz is applied to a series LCR circuit in which R = 3 Omega , L = 25.48 mH and C = 796 mu F . Find the impedance of the circuit.

A sinusoidal voltage of peak value of 283 V and frequency 50 Hz is applied to a series LCR circuit in which R = 3 Omega , L = 25.48 mH and C = 796 mu F . Find the power factor.

A sinusoidal voltage of peak value of 283 V and frequency 50 Hz is applied to a series LCR circuit in which R = 3 Omega , L = 25.48 mH and C = 796 mu F . Find the phase difference between the voltage across the source the current.

A sinusoidal voltage of peak value of 283 V and frequency 50 Hz is applied to a series LCR circuit in which R = 3 Omega , L = 25.48 mH and C = 796 mu F . Find the power dissipated in the circuit, and

A sinusoidal voltage of peak value 283 V and frequency 50 Hz is applied to a series LCR circuit in which R=6 Omega , L=50.96 mH and C=398 muF . Find the impedance of the circuit

A sinusoidal voltage of peak value 283 V and frequency 50 Hz is applied to a series LCR circuit in which R=6 Omega , L=50.96 mH and C=398 muF . Find the power factor

A sinusoidal voltage of peak value 283 V and frequency 50 Hz is applied to a series LCR circuit in which R = 3Omega, L = 25.48 mH, and C = 796 muF . Find (a) the impedance of the circuit, (b) the phase difference between the voltage across the source and the current, (c) the power dissipated in the circuit, and (d) the power factor.

A sinusoidal voltage of peak value 283 V and frequency 50 Hz is applied to a series LCR circuit in which R=6 Omega , L=50.96 mH and C=398 muF . Find the power dissipated in the circuit

A sinusoidal voltage of peak value 283 V and frequency 50 Hz is applied to a series LCR circuit in which R=6 Omega , L=50.96 mH and C=398 muF . Find the phase difference between the voltage across the source and the current .

For one series LCR ac circuit, 200 V, 50 Hz source is connected . Here R= 6 Omega , L=50.96 mH , C=398 muF , then find Impedance at resonance , current and resonance and power dissipated at resonance .