At 298 K temperature the activation energy for the reaction `x_2 + y_2 to 2xy + 20 kJ` is 15 kJ. What will be the activation energy for the reaction `2xy to x_2 + y_2`?

Options

A. `– 15 kJ `
B. `+35kJ`
C. `-5kJ`
D. `-35kJ`

Answer

B

Explanation

`Delta_RH`=activation energy of forward reaction
– activation energy of backward reaction
`rArr` -20= 15- ?
So , +35 kJ.