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If the edge of a body centred unit cell ...

If the edge of a body centred unit cell is 400 pm, what will be the approximate radius of the atom present in it? ( in pm)

A

200

B

141

C

173

D

924

Text Solution

Verified by Experts

The correct Answer is:
C
For BCC: `sqrt(3)a= 4R`
`R= (sqrt(3)a)/(4)= (sqrt(3) xx 400)/(4)= 173 Pm`
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