Home
Class 12
BIOLOGY
In deep freshwater ponds, different laye...

In deep freshwater ponds, different layers of water with different temperatures are known as
(A) Thermal stratification
(B) Surface tension
(C) Water equilibrium
(D) Thermal equilibrium

A

Thermal stratification

B

Surface tension

C

Water equilibrium

D

Thermal equilibrium

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

When does the systems at different temperature attained thermal equilibrium after time goes on ?

Two cylinders A and B of equal capacity are connected to each other via a stopcock. A contains a gas at standard temperature and pressure. B is completely evacuated. The entire system is thermally insulated. The stopcock is suddenly opened. Answer the following: (a) What is the final pressure of the gas in A and B ? (b) What is the change in internal energy of the gas ? (c) What is the change in the temperature of the gas ? (d) Do the intermediate states of the system (before settling to the final equilibrium state) lie on its P-V-T surface ?

Two narrow bores of diameters 3.0 mm and 6.0mm are joined together to form a U- tube open at both ends . If the U- tube contains water , what is the difference in its levels in the two limbs of the tube ? Surface tension of water at the temperature of the experiment is 7.3xx10^(-2)Nm^(-1) . Take the angle of contact to be zero and density of water to be 1.0xx10^(3)kgm^(-3)(g=9.8ms^(-2)) .

Two narrow bores of diameters 3.00mm and 6.0mm are joined together to form a U-tube open at both ends. If the U-tube contains water, what is the difference in its levels in the two limbs of the tube? Surface tension of water at the temperature of the experiment is 7.3 times 10^-2 N m^-1 .Take the angle of contact to be zero and density to water to be 1.0 times 10^3 kg m^-3

Diameters of the arms of a U tube are 10 mm and 1 mm . It is partially filled with water and it is held in a vertical plane . Find the difference in heights of water in both the arms . (Surface tension of water =70 dyne cm^(-1) angle of contact =0^(@).g=980cms^(-2))

A glass capillary tube is of the shape of a truncated cone with an apex angle alpha so that its two ends have cross sections of different radii. When dipped in water vertically, water rises in it to a high h, where the radius of its cross section is b. If the surface tension of water is S, its density if rho , and its contact angle with glass is theta , the value of h will be (g is the acceleration due to gravity)

Surafce tension is exhibited by liquids due to force of attraction between the molecules of the liquid .The surface tension decreases with increases in temperature and vanishes at boiling point Given that the latent heat of vaporization for water L_(v)=540(kcal)/(kg) the mechanical equivalent of heat J=4.2(J)/(cal) density of water rho_(w)=10^(3)kgl^(-1) ,Avogadro'sno. N_(A)=6.0xx10^(26)k " mole"^(-1) . Molecular weight of water M_(A)=10kg , for 1k mole . (a) Estimate the energy required for one molecule of water to evaporated. (b) Show that the inter molecular distance for water is d=((M_(A))/(N_(A))xx(1)/(rho_(w)))^((1)/(3)) and find its value. (c ) 1 g of water in the vapour state at 1 atm occupies 1601cm^(3) , estimate the intermolecular distance at boiling point in the vapour state. (d) During vaporisation a molecule overcomes a force F, assumed constant to go from an inter molecular distance d to d .Estimate the value of F. (e ) Caculate (F)/(d) , which is a measure of the surface tension.

Which of the following exploits energy due to temperature difference at surface water and water at depth ?

The key elements that lead to mean variation in the conditions of different habitat, are :- (A) Temperature, water, light and soil (B) parasite, pathogen, predators & competitors of the organism (C) The physico-chemical (abiotic) components characterise the habitat of an organism

Four open organ popes of different length and different gases at same temperature as shown in figure. Let f_(A),f_(B),f_(C) and f_(D) be their fundamental frequencies then : [Take gamma_(CO_(2)) = 7//5 ] .