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The electronegativities of F and H are 4...

The electronegativities of F and H are 4.0 and 2.1 respectively. The percent ionic character in H and F bond is

A

43

B

34

C

94

D

39

Text Solution

Verified by Experts

The correct Answer is:
A
`%` of ionic character `=16(4.0-2.1)+3.5(4.0-2.1)^(2)`
=43%
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OMEGA PUBLICATION-CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES-Multiple Choice Questions (MCQs)
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  13. How does ionisation energy vary along a period and down a group ?

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