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In a process , 701 j of heat is absorbed...

In a process , 701 j of heat is absorbed by a system and 394 j of work is done by the system. What is the change in internal energy for the proces ?

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We are given system = 701 J
Work done by the system = - 394 j
We are to calculate the internal energy. We know that
According to first law of thermodynamics, `Delta U or Delta E = q + w`
Substituting the values, we get
`Delta U or Delta E = 701 - 394 = 407 j`
So, change in internal energy is 407 j.
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OMEGA PUBLICATION-THERMODYNAMICS-MULTIPLE CHOICE QUESTIONS (MCQ)
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