Does the stem prepare food for any plant?

Explanation

We are given that
(i) `2C_(3)H_(8) + 10 O_(2) to 6CO_(2) + 4H+_(2)O , Delta H = 2220.2 xx 2 = 4440.4`
(ii) `8[H_(2)+""^(1//2)O_(2) to H_(2)O], Delta H = - 285.8 xx 8 = 2286.4`
`6[C+O_(2) to CO_(2)], Delta H = - 393.5 xx 6 = 2361.0`
we are to find out the standard enthalpy of formation of propose.
(iv) `6C + 8H_(2) to 2C_(3) H_(g),Delta H`
By adding (iii) and (iv) we get,
`8H_(2) 6C to 2C_(3)H_(g),Delta H = 207 kJ`
Standard enthalpy of formation of propane = `(2C_(3)H_(s))/(2) = (207)/(2) = 103.5 kj/mol`