Home
Class 11
CHEMISTRY
The equilibrium constant for a reaction...

The equilibrium constant for a reaction is 10. What will be the value of `Delta G^(@)` ?
R = 8.314 `jK^(-1) mol^(-1), T = 300K`.

Text Solution

Verified by Experts

We are given that
`K_(c) = 10 T = 300 K R = 8.314 jK^(-1)mol^(-1)`
We are to find out the value of `Delta G^(@)`.
Using the relation,
`Delta G^(@) = - 2.303 RT log K_(c) = - 2.303 xx 8.314 xx 300 K log 10`
`= - 2.303 xx 8.314 xx 300 xx 1 = - 5744 j mol^(-1) = - 5.744kj mol^(-1)`.
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    OMEGA PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS (MCQ)|25 Videos

  • THE S-BLOCK ELEMENTS

    OMEGA PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS MCQ.s|26 Videos

Similar Questions

Explore conceptually related problems

Calculate the equilibrium constant for the reaction at 298K Cu(s)+Cl_(2)(g)toCuCl_(2)(aq) Given that R=8.314JK^(-1)mol^(-1) , E^(@)Cu^(2+)//Cu=0.34V , E^(@)(1)/(2)Cl_(2)//Cl^(-)=1.36V F=96500C" "mol^(-1)

The standard free energy change of a reaction is DeltaG^(@)=-115kJ//mol^(-1) at 298 K. Calculate the value of log_(10)K_(p) (R=8.314JK^(-1)mol^(-1))

The rate of a reaction increases four times when the temperature changes from 300 K to 320 K. Calculate the energy of activation of the reaction assuming that it does not change with temperature (R = 8.314 JK^-1 mol^-1) .

In general it is observed that the rate of a chemical reaction becomes double for every 10^@ rise in temperature. If this generalisation holds for a reaction in the temperature range 2908 K to 398 K, what would be the value of activation energy for the reaction. (R=8.314 J K^(-1)mol^(-1) )

The rate of reaction becomes four times when the temperature changes from 293 K to 313 K. Calculate the energy of activation (E _(a)) of the reacton assuming that it does not change with temperature. [ R = 8.314 J K ^(-1) mol ^(-1), log 4 = 0. 6021]

If 10^(-4) dm^(3) of water is introduced into a 1.0 dm^(3) flask to 300K how many moles of water are in the vapour phase when equilibrium is established ? (Given vapour pressure of H_(2)O at 300K is 3170Pa R =8.314 JK^(-1) mol^(-1)) .

The equilibrium constant K_(c) for the following reaction at 842^(@)C is 7.90xx10^(-3) .What is K_(p) at same temperature ? (1)/(2)f_(2)(g)hArrF(g)

OMEGA PUBLICATION-THERMODYNAMICS-MULTIPLE CHOICE QUESTIONS (MCQ)
  1. The equilibrium constant for a reaction is 10. What will be the value...

    Text Solution

    |

  2. The intensive property among these quantities is

    Text Solution

    |

  3. Identify the extensive property among the followings

    Text Solution

    |

  4. An adiabatic expansion of an ideal gas always has

    Text Solution

    |

  5. During isothermal expansion of an ideal gas, its

    Text Solution

    |

  6. Enthalpy of a reaction Delta H is expressed as

    Text Solution

    |

  7. The heat required to raise the temperature of a body by 1C degree is c...

    Text Solution

    |

  8. According to the second law of thermodynamics , a process (reaction is...

    Text Solution

    |

  9. Considering entropy (S) as a thermodynamic parameter the criterion fo...

    Text Solution

    |

  10. Delta G = Delta H - T Delta S was given by

    Text Solution

    |

  11. What is pistil?

    Text Solution

    |

  12. The occurrence of reaction is impossible if

    Text Solution

    |

  13. One calorie is equivalent to

    Text Solution

    |

  14. For an adiabatic proces which of the following relations is correct ?

    Text Solution

    |

  15. For the reactions : C(s) + O(2) (g) to CO(2) (g)

    Text Solution

    |

  16. For the reaction : C(3)H(8)(g) + 5O(2) (g) to 3 CO(2) (g) + 4H(2) O...

    Text Solution

    |

  17. Which one of the following expressions represents the first law of the...

    Text Solution

    |

  18. For a reaction N(2(g)) + 3H(2(g)) hArr 2NH(3(g))

    Text Solution

    |

  19. What do mean by the term- Weed?

    Text Solution

    |

  20. What are trees? Give two examples?

    Text Solution

    |

  21. For a reversible process at equilibrium, the change in entropy may be ...

    Text Solution

    |