Home
Class 11
CHEMISTRY
For the reaction : C(3)H(8)(g) + 5O(2...

For the reaction :
`C_(3)H_(8)(g) + 5O_(2) (g) to 3 CO_(2) (g) + 4H_(2) O (l)` at constant temperature `Delta H - Delta U`

A

`+ RT`

B

`- 3RT`

C

3RT

D

`-RT`

Text Solution

Verified by Experts

The correct Answer is:
B
For `C_(3) H_(g) (g) + 5O_(2) (g) to + 3CO_(2) (g) + 4H_(2) O(l),`
`Delta n_(g) = 3 - 6 = -3 , therefore Delta H = Delta U - 3RT`
`rArr Delta H - Delta U = - 3RT`
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    OMEGA PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS (MCQ)|25 Videos

  • THE S-BLOCK ELEMENTS

    OMEGA PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS MCQ.s|26 Videos

Similar Questions

Explore conceptually related problems

For the reactions : C(s) + O_(2) (g) to CO_(2) (g)

The internal energy change (Delta U) for reaction CH_(4)(g) + (20_(2)(g) to CO_(2) (g) + 2H_(2) O(l) is -885.5 kj/mol at 298K. What is Delta H at 298 K?

For a reaction N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g))

Consider the following reaction. C_(6)H_(6)(l)+(15)/(2)O_(2)(g)rarr6CO_(2)(g)+3H_(2)O(g) signs of DeltaH, DeltaS and DeltaG for the above reaction will be a) +,-,+ b) -,+,- c) -,+,- d) +,+,-

Calculate the enthaply change in the reaction, CH_(4)(g) + 2O_(2)(g) to CO_(2)(g) + 2H_(2)O (i)The enthalpy change of formation of CH_(4) (g), CO_(2)(g) and H_(2)O (i) are - 74.8 kj mol^(-1), -393.5 KJ mol^(-1) and - 286 KJ mol^(-1) respectively.

Calculate the standard enthaply of formation of CH_(3) OH(l) from the following data CH_(3) OH (l) + (3)/(2) O_(2) (g) to CO_(2) (g) + 2H_(2)O (l) , Delta_(r) H^(@) = - 726 kj/mol C(g) + O_(2) (g) to CO_(2) (g), Delta_(c) H^(@) = - 393 kj/mol H_(2)(g) + (1)/(2) O_(2) (g) to H_(2) O(l) : Delta_(f) H^(@) = - 286 kj /mol

Balance the following equation : CH_4(g) +O_2(g) rarr CO_2 (g)+H_2O(l)

Consider the reacting at 300K C_(6)H_(6)(l)+(15)/(2)O_(2)(l)rarr 6CO_(2)(g)+3H_(2)O(l),DeltaH=-3271 kJ What is DeltaU for the combustion of 1.5 mole of benzene at 27^(@)C ?