In a reaction, `2A rarr Products`, the concentration of A decreases from 0.5 mol L^(-1) to `0.4 molL^-1` in 10 minutes. Calculate the rate during this interval?

Explanation

We are given that
Chemical reaction ` 2 A to 4 B + C`
`[B] = 5 xx 10 ^(-3) mol L ^(-1)`
`dt = 10` seconds
Using the relation, Rate of reaction `=- (1)/(2) ( Delta [A])/( Delta t ) = + (1)/(4) (d [B])/( dt )`
`=- (1)/(2) (Delta [A])/( Delta t ) = ( 1)/(4) xx (5 xx 10 ^(-3))/( 10 ) = 1. 25 xx 10 ^(-4) ,- (Delta [A])/( Delta t ) = 2 xx 1. 25 xx 10 ^(-4) = 2. 5 xx 10^(-4) mol L ^(-1) s ^(-1)`
i.e. Rate of disappearence of `A = 2. 5 xx 10 ^(-4) mol L ^(-1) s ^(-1)`