The rate of a reaction `2A+B rarr A_2B`.
has rate law : rate = k `[A]^2` with the rate constant equal to 0.50 `mol^(-1)" L sec"^(-1)`. Calculate the rate of reaction when
(i) [A] = 0.60 mol `L^(-1)`, [B] =-0.05 mol `L^(-1)` and
(ii) When concentration of A and B have been reduced to 1/4 th

Explanation

`A to B`
`r = K [A],` Where `K = 0. 50 sec ^(-1)`
`r = K [A]`
`2. 4 xx 10 ^(-2) = 0. 50 xx [A]`
`[A] = ( 2. 4 xx 10 ^(-2))/( 0. 5) , [A] = 4. 8 xx 10 ^(-2) mol L ^(-1)`