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Bond angle in (PH4)^+ is higher than tha...

Bond angle in `(PH_4)^+` is higher than that in `PH_3`. Why?

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It can be explained on the basis ofelectronegativity. Electronegativity decreases from oxygen to tellurium. Electron density also decreases down the group. There is maximum electron density in case of `H_(2)O`. This leads to maximum electronic repulsion. Hence, the bond angle is maximum in `H_(2)O`.
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