How are `XeO_3` and `XeOF_4` prepared?

Explanation

Preparation of `XeO_3 and XeO_F_2`
`XeF_(6) + 3H_(2)O rarr XeO_(3)` + 6HF`
`XeF_(6) + 2H_(2)O rarr XeO_(2)F_(2) + 4HF`
Shape of `XeO_(3)`
Hybridisation of Xe = 1/2 [ 8 + 0 - 0 + 0) = 4 = `sp^(3)`.
Hence, its shape is pyramidal.

Shape of `XeO_(2)F_(2)`
Hybridisation = 1/2 [ 8 + 2 - 0 + 0] = 5 = `sp^(3)d`.
Hence, its shape is trigonal bipyrarnidal.