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Give the formula of the noble gas specie...

Give the formula of the noble gas species which is isostructural with `lCl_4^-`.

Text Solution

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In `ICl_(4)^(-)` , Cl atom is more electronegative. So negative charge should be on Cl atom. No. of electrons in the valence shell of I atom = 7. Charge provided by Cl atom = `4 xx 1` = 4 Charge on central atom = I Total number of electrons surrounding central atom = 7 + 4 + 1= 12. 12.
Electron pair surrounding central atom = 12/2 = 6
No of bonds (I-Cl bond) = 4
Lone pair = 2 ( 6 - 4 = 2)
Noble gas compound having 12 electrons in valance shell of central atom is `XeF_(4)`.
According to VSEPR theory shape of both is square planar.
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