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A cricketer can throw a ball to a maximu...

A cricketer can throw a ball to a maximum horizontal distance of 100 m. How much high above the ground can the cricketer throw the same ball ?

Text Solution

Verified by Experts

We are given : `R _( max) = 100 m`
We are to calculate : `H _(max)`
We know that , `R _(max) = (u ^(2))/( g)` (For angle of projection `theta = 45 ^(@))`
On substituting the values, we get
We can write `( u ^(2) )/(g) = 100 or u ^(2) = 100 xx g`
Also for maximum height `H _(max) = ( u ^(2))/( 2 g) implies H_(max) = (100xx g)/( 2 xx g) = 50 m.`
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Knowledge Check

  • A ball is thrown up and attains a maximum height of 100 m. Its initial speed was

    A
    9.8m/s
    B
    44.2m/s
    C
    19.6m/s
    D
    98m/s

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