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Given W = vecF.vecS = 0 and vecF != 0, v...

Given `W = vecF.vecS = 0` and `vecF != 0, vecS != 0` Then:

A

`vecF _|_ vecS`

B

`vecF = vecS`

C

`vecF || vecS`

D

none of the above is true.

Text Solution

Verified by Experts

The correct Answer is:
A
`W == vecF.vecS ` As `W = 0 implies vecF _|_vecS`
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