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Two point masses each of 10 g are placed...

Two point masses each of 10 g are placed 10 cm apart. The centre of mass of the system is located at:

A

5 cm from the centre of either mass

B

7 cm from the centre of either mass

C

9 cm from the centre of either mass

D

11 cm from the centre of either mass.

Text Solution

Verified by Experts

The correct Answer is:
A
`R_("c.o.m")=(m_1r_1+m_2r_2)/(m_1+m_2)=(10xx5+10xx5)/(20)`
=`(100)/(20)=5cm`
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