Stefan Boltzman law : `E=esigma(T^(4)-T_(0)^(4))` where E is emittance , e is emissivity , `sigma` is Stefan 's constant , T is temperature of body , `T_(0)` is temperature of surroundings . Is the statement true?

Stefan 's Law : EpropT^(4)orE=sigmaT^(4) , where sigma is Stefan 's constant .Its value is 5.07xx10^(-9)-Jm^(-2)K^(-4)"second"^(-1) . Is the statement true?

Solar Constant (s) : s =((r )/(R ))^(2)sigmaT^(4) , where r= radius of sun ,R= distance of the earth from the centre of sum , T= absolute temperature of sun . Value of solar constant is 1.937 "cal cm"^(-2) "min"^(-1) . Is the statement true?

Newton 's Law of Cooling : According to Newton 's law of cooling the rate of cooling is directly proportional to the temperature difference of body and its surrounding .If body cools from theta_(1) "to" theta_(2) in t seconds then (ms(theta_(1) -theta_(2))/(t)=alpha[(theta_(1)+theta_(2))/(t)- theta_(0)] . Where theta_(0) is the temperature of the surrounding . Is the statement true?

The position time graph of a body of mass 2 kg is as given in the figure. What iws the impulse on the body at t = 0 s and t = 4 s.

Which one of the following relationships when graphed does not give a straight line for helium gas? I. K.E. and T at constant pressure and volume II. P v/s V at constant temperature for a constant mass III. V v/s 1/T at constant pressure for a constant mass

If lambda _m is the wavelentgh corresponding to maximum radiation for a body at temperature T,then which of the following relations is true?

A body executes S.H.M. The P.E. and K.E and total energy (T.E) are measured as function of displacement x . Which of the following statement is true?

The temperature T of a cooling drops at a rate proportional to the difference T-S, where S is the constant temperature of surrounding medium. A thermometer reading 80^@F was taken outside. Five minutes later, the thermometer read 60^@F . After another five minutes the reading was 50^@F . what was the outside temperature?

The temperature T of a cooling object drops at a rate proportional to the difference T-S, where S is the constant temperature of the surrounding medium. Thus, (dT)/(dt)=-k(T-S) , where k(>0) is constant and t is the time. Solve the differntial equation if it is given that T(0)=150.