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The displacement of a particle executing...

The displacement of a particle executing simple harmonic motion is given by `y=10sin (30t+0.6)` Write down amplitude and time period.

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We are given :
`10sin(30t+0.6)` . .. (i)
We are to calculate : Amplitude (A) and time period (T)
Comparing equation (i) and (ii), we get
`omega =30rArr(2pi)/(T)=30`
`T=(2pi)/(30)=(2xx3.14)/(30)`
`T=0.21s`.
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