Show that phase difference between
displacement and velocitu is `pi//2` radians.

Explanation

The displacement of a particle executing SHM is given by
`y=A sin omegat`
Now, velocitu of the particle is given by
`v=(dy)/(d)=a omega cos t = a omegasin(omegat+(pi)/(2))` . . . (ii) `[becausecos theta=sin(theta+(pi)/(2))]`
From equation (i) and (ii). it is clear that phase difference displacement and velocity is `pi//2`