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The period of oscillation of a simple pe...

The period of oscillation of a simple pendulum of constant length at earth's surface is T. Its period inside a mine is :

A

greater than T

B

less than T

C

equal to T

D

can not be compared

Text Solution

Verified by Experts

The correct Answer is:
A
As `T prop (1)/(sqrt(g))` for simple pendulum, so time period of simple pendulum is greater than g as value of g is less in mine.
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