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If the length of a simple pendulum is ha...

If the length of a simple pendulum is halved, its period is

A

increased by a factor of `sqrt(2)`

B

halved

C

remains same

D

decrease by a factor of `1//sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
As `T prop sqrt(l)`
when `l.=(l)/(sqrt(2))` so `T.=(T)/(sqrt(2))`.
Therefore, time period decreases by a factor of `(1)/(sqrt(2))`.
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