Formula mass of NaCl is `58.45 g mol^-1` and density of its pure form is `2.167 g cm^-3`. The average distance between adjacent sodium and chloride ions in the crystal is `2.814xx10^-8 cm`. Calculate the Avogadro number.

KF has NaCl structure. What is the distance between K^+ and F^- if density is 2.48 g cm^-3 ?

Chromium crystallizes in a body centred cubic lattice whose density is 7.20g/cm^3 . The length of the edge of the unit cell is 288.4 pm. Calculate the Avogadro number (atomic mass of chromium=52).

An element having a density 11.2"g cm"^(-3) forms a fcc lattice with edge of 4xx10^(-3) cm. Calculate the atomic mass of the element.

Silver crystallines in fcc lattice. If edge length of the cell is 4.077xx10^-8cm and density is 10.5 g cm^-3 . Calculate the atomic mass of silver.

A magnet weighs 75 g and its magnetic moment is 2xx10^-4 A m^2 . If the density of the material of the magnet is 7.5 xx 10^3 kg m^-3 , calculate the intensity of magnetisation.

Calculate the value of Avogadro's number from the following data Density of NaCl=2.165"g cm"^(-3) . Distance between Na^(+)andCl^(-) in NaCl crystal = 281 pm.

Silver crystallises in fcc lattice. If edge length of the cell is 4.04x10^(-8) cm and density is 10.5g cm^(-3) , calculate the atomic mass of silver.

The well known mineral fluorite is chemically clacium fluoride. Its is known that in one unit cell of this mineral there are 4 Ca^(2+) ions and 8 F^- ions and that of Ca^(2+) ions are arranged in a fcc lattice. The F^- ions fill all the tetrahedral holes in the face centred cubic lattice of Ca^(2+) ions. the edge of hte unit cell is 5.46xx10^-8 cm in length. the density of the solid is 3.18 gcm^-3 . use this information to calculate the Avagadro's number. (Molar mass of CaF_2=70.08 g mol^-1 ).